x^2-32x-768=0

Solution for x^2-32x-768=0 equation:

x^2-32x-768=0

a = 1; b = -32; c = -768;
Δ = b2-4ac
Δ = -322-4·1·(-768)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-64}{2*1}=\frac{-32}{2}
=-16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+64}{2*1}=\frac{96}{2}
=48
$